Two angles are said to be complementary, if the sum of the two angles is 90 degrees.
Given that the measure of angle SWT is 50 degrees, thus, the measure of the complementary angles will be 90 - 50 = 40 degrees.
From the diagram, the measure of angle USP is 40 degrees, hence it is a complement of angle SWT.
Recall that the angle on a straight line is equal to 180 degrees, thus the sum of the measures of angles USP, WST and TSV is 180 degrees.
i.e. mUSP + mWST + mTSV = 180 degrees
40 + 100 + mTSV = 180
mTSV = 180 - 140 = 40 degrees.
Hence angle TSV is complementary to angle SWT.
Therefore, the complementary angles to angle SWT are angle USP and angle TSV.
Answer:
r=-45
Step-by-step explanation:
r/5=-9
x 5 x5
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r=-45
Hope this helps ∞<3
Hello!
Since the angles are same side alternate angles they are equal to each other
60 - 2x = 70 - 4x
We solve this algebraically
Add 4x to both sides
60 + 2x = 70
Subtract 60 from both sides
2x = 10
divide both sides by 2
x = 5
Hope this helps!
Answer:
See below.
Step-by-step explanation:
Here's an example to illustrate the method:
f(x) = 3x^2 - 6x + 10
First divide the first 2 terms by the coefficient of x^2 , which is 3:
= 3(x^2 - 2x) + 10
Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form
(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.
= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)
= 3 [(x - 1)^2 -1 ] + 10
= 3(x - 1)^2 - 3 + 10
= <u>3(x - 1)^2 + 7 </u><------- Vertex form.
In general form the vertex form of:
ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .
This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.
