(x^2+5x-36)/(x^2-16)
=(x^2+9x-4x-36)/(x^2-4^2)
=x(x+9)-4(x+9)/(x+4)(x-4)
=(x-4)(x+9)/(x+4)(x-4)
=x+9/x+4
Hope this helps.
Um i would need more details
But i thing you would add those together
Answer:
-7/4
Step-by-step explanation:
You are looking for the composite g(f(2)). The simplest way to solve this is to evaluate f(2) and enter the solution in to your g function.
g(f(2))=g(-(2)^2-2(2)+4)=g(-4-4+4)=g(-4)
g(-4)=4/(-4(-4)-2)=4/(16-2)=4/14=2/7
Therfor, g(f(2))=2/7 **I'm assuming the -4x-2 is all in the denominator of the g(x) function. If -2 is not in the denominator you would have
g(f(2))=4/(-4(-4)) -2=4/16 -2=1/4 -2=1/4-8/4= -7/4
Answer:
p(on schedule) ≈ 0.7755
Step-by-step explanation:
A suitable probability calculator can show you this answer.
_____
The z-values corresponding to the build time limits are ...
z = (37.5 -45)/6.75 ≈ -1.1111
z = (54 -45)/6.75 ≈ 1.3333
You can look these up in a suitable CDF table and find the difference between the values you find. That will be about ...
0.90879 -0.13326 = 0.77553
The probability assembly will stay on schedule is about 78%.
