X-rays differ from the light source readout in terms of the intensity and the possible damage that can be obtained from the two radiation types. The light source readout is more damaging than the X-rays readout in the gizmo. Therefore, precaution is required when handling the light source readout in the gizmo.
Answer:
oxidation occurs at the cathode.
Explanation:
In a voltaic cell electrons move from anode to cathode. At the anode, species give up electrons. This is an oxidation reaction depicted by the oxidation half equation. At the cathode, species accept electrons and become reduced. This is depicted by the reduction half equation. In summary; in a Voltaic cell, oxidation occurs at the anode while reduction occurs at the cathode.
To determine the mass of gold, we simply multiply the density and volume. Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We do as follows:
mass = density x volume
mass = 19.3 g/cm^3 ( 16.0 cm^3 )
mass = 308.8 g
The element found in the liver that helps prevent anemia is iron.
Iron is an essential element for blood production. Close to 70% of the body's iron is found in the red blood cells. In the red blood cells it is a vital ingredient of hemoglobin, the red pigment that gives blood its red color. In the muscle cells, iron is found as myoglobin.
Iron is stored mostly in the liver as ferritin or hemosiderin.
When iron stores are finished or exhausted, the condition is called iron depletion. When the shortage of iron is severe, it results in a condition known as iron deficiency anemia whereby the red blood cells do not have enough hemoglobin.
Answer:
0.6258 g
Explanation:
To determine the number grams of aluminum in the above reaction;
- determine the number of moles of HCl
- determine the mole ratio,
- use the mole ratio to calculate the number of moles of aluminum.
- use RFM of Aluminum to determine the grams required.
<u>Moles </u><u>of </u><u>HCl</u>
35 mL of 2.0 M HCl
2 moles of HCl is contained in 1000 mL
x moles of HCl is contained in 35 mL
We have 0.07 moles of HCl.
<u>Mole </u><u>ratio</u>
6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)
Hence mole ratio = 6 : 2 (HCl : Al
- but moles of HCl is 0.07, therefore the moles of Al;
Therefore we have 0.0233333 moles of aluminum.
<u>Grams of </u><u>Aluminum</u>
We use the formula;
The RFM (Relative formula mass) of aluminum is 26.982g/mol.
Substitute values into the formula;
The number of grams of aluminum required to react with HCl is 0.6258 g.
