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2 years ago

Given the graph of a radical function which statement is correct

Mathematics

1 answer:

Romashka [77]2 years ago

6 0

Option D is correct. The correct statement that represents the graph is R: {y E R | y ≥ -3}

From the given graph, we are to get the range.

The range is the output value for which the function of the graph exists. The required output values are the y-values.

From the graph shown, we can see that the range of y is from -3 to 1. This can be denoted as;

Range = [-3, 1)

This shows that the range of the graph are all the values greater than -3 including -3.

The correct statement will therefore be;

R: {y E R | y ≥ -3}

Learn more about range here: brainly.com/question/17611901

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4% of 50 Percent of a quantity M

Ksivusya [100]

Answer:

4% of 50 is 2

Step-by-step explanation:

6 0

2 years ago

Please help: linear algebra problem. (Linear combinations)

DochEvi [55]

Answer:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

$A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]$

$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

3 0

2 years ago

Julie gives 7 pieces of candy to each of her friends. If Julie gives all of her candy away, which amount of candy could have bee

True [87]

To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.

161/7=23
162/7=23.1428571429
145/7=20.7142857143
128/7=18.2857142857

Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.

The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.

5 0

2 years ago

Read 2 more answers

Can I get some help plz thank u sm

weeeeeb [17]

Answer:

x = 72

hope it helps

5 0

2 years ago

Question number 8. Prove that 3 + √5 is an irrational number.

Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

$\\ \sf \: 3 + \sqrt{5} = \frac{a}{b} \\ \\ \qquad \: \tiny \sf{(where \: \: a \: \: and \: \: b \: \: are \: \: integers \: \: and \: \: b \: \neq \: 0)} \\$

$\\ \sf \: \sqrt{5} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \\$

Since, a, b and 3 are integers. So,

$\\ \sf \: \frac{p - 3b}{b} \\ \\ \qquad \tiny \sf{ \: (is \: \: a \: \: rational \: \: number \:) } \\$

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

$\\$

Hence, 3 + √5 is an irrational number.

7 0

2 years ago