We have y = -2 - 2x ;
Then, x + ( -2 - 2x ) = 5 ;
x - 2 - 2x = 5;
- x - 2 = 5 ;
-x = 7 ;
x = - 7;
Finally, y = - 2 - 2 × ( - 7 ) ;
y = - 2 + 14 ;
y = 12;
<span>The x coordinate of the solution to the system is - 7 .</span>
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The answer is A, 1. In the statement x^2 >x, if we try 4, 5 and 8 for x, we get 16, 25 and 64 for x^2. The statement is true. But if we try x = 1, when we square it we still have 1. Therefore for x=1, x^2>x is false.
For a function, domain means the x value & range is the y value. So, simply, substitute each value in the domain for the x in your function, and you'll find the range.
Here're the answers:
g(0)=(0)^2+2
g(0)=2
g(2)=(2)^2+2
g(2)=6
g(5)=(5)^2+2
g(5)=27
g(9)=(9)^2+2
g(9)=83
Hope this helps!