Answer:
All real numbers
Step-by-step explanation:
One way to do it is with calculus. The distance between any point
on the line to the origin is given by
Now, both
and
attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.
Solving for
, you find a critical point of
.
Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.
You have
so indeed, a minimum occurs at
.
The minimum distance is then
The answer is going to be 2*sqrt(5). You have to split it into perfect squares for it to be simplified... so in this case, I had sqrt(4*5) because sqrt(4) can be simplified... so your answer would be sqrt(4)*sqrt(5) or 2sqrt(5)
Answer:
8
Step-by-step explanation:
Here the velocity of initial velocity is 40 & final is 0 so use formula
The <em>correct answer</em> is:
f(x) = -10x², f(x) = 2x², and f(x) = 0.5x²
Explanation:
For a quadratic in standard form, f(x) = ax²+bx+c, the value of a describes the width and direction of the parabola. If a is positive, the parabola is open upward. If a is negative, the parabola is open downward.
If a < 1, a fraction or decimal, the graph is wider than the parent function f(x)=x². If a > 1, the graph is narrower than the parent function f(x)=x². The larger the value of a is (a > 1), the narrower the graph is. This makes the function with the decimal value of a the widest; the remaining graphs are in order of the value of a, least to greatest.