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2 years ago

15

Determine the value of x

1 answer:

Mekhanik [1.2K]2 years ago

6 0

Answer:

2√2

Step-by-step explanation:

<u>By </u><u>using </u><u>trigonometry,</u>

sin 45° = x/4

x = 4sin 45°

x = 2√2

<u>By </u><u>using </u><u>Pythagorean</u><u> </u><u>theorem</u><u>,</u>

Since you know that it is an isosceles triangle and it's also a right-angled triangle,

4² = x² + x²

16 = 2x²

x² = 8

x = √8

= 2√2

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Solve the simultaneous equations<br> y = 9 - X<br> y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

3 0

2 years ago

Give brainlest on time limit pls help

inysia [295]

Answer:

336 sq un

Step-by-step explanation:

The area of a rhombus is pq/2 where p and q are the diagonals.

you have:

p = 12 + 12 = 24

q = 18 + 10 = 28

so the formula would be:

24 * 28 / 2 = 336 sq un

8 0

2 years ago

The annual rent of a room in Kathmandu is 60000. Find the rent of five months.

Oksanka [162]

Answer:

the rent room in Kathmandu =60000

the rent of five is =5×60000

the total value=300000

5 0

2 years ago

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Which value of h would horizontally translate a parabola to the right 4 units?

bonufazy [111]

The answer is -4 for it to be translated right.

6 0

2 years ago

Any one know geometry please help me out

MA_775_DIABLO [31]

Answer:

X = 4

Step-by-step explanation:

And then the nearest tenth would be 0

cause all numbers that have 4 round to like 0 or the tenth under it. If it has a five or higher it rounds to 10 or the number above it

7 0

2 years ago

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