Using the normal distribution, we have that:
- The distribution of X is
.
- The distribution of
is 
.
- 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
- 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem, the parameters are given as follows:
Hence:
- The distribution of X is .
- The distribution of is .
The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:
X = 58:
Z = 0.05.
Z = 0.05 has a p-value of 0.5199.
X = 55:
Z = -0.1.
Z = -0.1 has a p-value of 0.4602.
0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
For the sample of 17 movies, we have that:
X = 58:
Z = 0.19.
Z = 0.19 has a p-value of 0.5753.
X = 55:
Z = -0.38.
Z = -0.38 has a p-value of 0.3520.
0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.
More can be learned about the normal distribution at brainly.com/question/4079902
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Answer:
A 99% confidence interval will be wider than a 95% confidence interval
Step-by-step explanation:
From the question we are told that
The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm
Generally the width of a confidence interval is dependent on the margin of error.
Generally the margin of error is mathematically represented as
From the above equation we see that
Here 
is the critical value of the half of the level of significance and this value increase as the confidence level increase
Now if a 99% confidence level is used , it then means that the value of
will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval
Hence a 99% confidence interval will be wider than a 95% confidence interval
Given a N quantity of numbers, the Geometric Mean is equal to the N-th root of product of the N numbers
In this case, we have two numbers, then we need to multiply them and take square root:
![\sqrt{40\cdot15}=\sqrt[]{600}=\sqrt[]{100\cdot6}=\sqrt[]{100}\cdot\sqrt[]{6}=10\sqrt[]{6}](https://tex.z-dn.net/?f=%5Csqrt%7B40%5Ccdot15%7D%3D%5Csqrt%5B%5D%7B600%7D%3D%5Csqrt%5B%5D%7B100%5Ccdot6%7D%3D%5Csqrt%5B%5D%7B100%7D%5Ccdot%5Csqrt%5B%5D%7B6%7D%3D10%5Csqrt%5B%5D%7B6%7D)
The answer is:
10√6
Rounded is Approximately 24.5
Answer:
27, 30, 33
Step-by-step explanation:
Since Sam has fewer number of baseball cards than Jill who has 36 baseball cards and can arrange all his cards in only three ways, the possible number of baseball cards that Sam could have is 27, 30 or 33.
If he has 27 baseball cards, he can arrange 9 baseball cards per row in 3 rows
If he has 30 baseball cards, he can arrange 10 baseball cards per row in 3 rows
If he has 33 baseball cards, he can arrange 11 baseball cards per row in 3 rows
Answer:
9 ft
Step-by-step explanation:
its volume is equal to the area by height;
(2.5 x 3)h = 67.5
h = 9ft
