Answer:
5i and -5i
Step-by-step explanation:
Imaginary roots come in pairs, so the third root must be a real number. Therefore, neither 5i nor -5i can be the third root.
Answer:
12
Step-by-step explanation:
Since TSQ and QSR are supplementary, they give 180 when summed. TSQ is 150, so QSR must be 30.
Therefore, you have
Answer:(X+Y)²
X²+Y² would be greater than X²-Y² since addition gives a greater result than subtraction.
X²+Y² would be greater than 2(X+Y); this is because 2(X+Y) = 2X+2Y, which will be less than X²+Y², since X>Y.
(X+Y)² = (X+Y)(X+Y). This can be simplified using the distributive property:
X(X)+X(Y)+Y(X)+Y(Y) = X²+XY+YX+Y² = X²+2XY+Y². This is greater than X²+Y².
