Answer:
Explanation:
<u>1. Using the minimun number of sheets of paper in the interval [300, 400]</u>
a) Cost: $ 2.00 / 100 sheets
b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day
c) Approimately 20 school days per month:
- $ 6.00 / day × 20 day = $ 120.00
<u>2. Using the maximum number of sheets of paper in the interval [300, 400]</u>
a) Cost: $ 2.00 / 100 sheets
b) 400 sheets / day × $ 2.00 / 100 sheets = $ 8.00 / day
c) Approimately 20 school days per month:
- $8.00 / day × 20 day = $ 160.00
<u>3. Middle value:</u>
Calculate the middle value between $160.00 and $120.00
- [$120.00 + $160.00] / 2 = $140.00
Thus, the answer is the option A.
Answer:
$384.75
Step-by-step explanation:
Albert's hourly pay is $8.10
When he works for more than 40 hours, his hourly pay will increase to $12.15.
Last week, Albert worked for 45 hours, his hourly pay would be:
First 40 hours = $8.10 * 40 = $324
Remaining 5 hours =
$12.15 * 5 = $60.75
Albert gross pay for this period will be calculated as:
$324 + $60.75 = $384.75
Therefore, Albert gross pay for this period = $384.75
Answer:
(- 1, 1 )
Step-by-step explanation:
Given the 2 equations
2x - y = - 3 → (1)
x + y = 0 → (2)
Adding the 2 equations term by term will eliminate the term in y, that is
3x = - 3 ( divide both sides by 3 )
x = - 1
Substitute x = - 1 into either of the 2 equations and solve for y
Substituting into (2)
- 1 + y = 0 ( add 1 to both sides )
y = 1
Solution is (- 1, 1 )
$88.50 you just add btw.just letting u know
Answer:
$630.50
Step-by-step explanation: