Answer:
a = p * q
b = p * s + q * r
c = r * s
Step-by-step explanation:
In the trinomial ax² + bx + c
a is the coefficient of x²
b is the coefficient of x
c is the numerical term
∵ The trinomial is ax² + bx + c
∵ Its factors are (px + r) and (qx + s)
∴ ax² + bx + c = (px + r)(qx + s)
∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)
∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs
∴ ax² + bx + c = pqx² + (ps + qr)x + rs
→ By comparing the two sides
∵ ax² = pqx² ⇒ divide both sides by x²
∴ a = pq
∵ bx = (ps + qr)x ⇒ Divide both sides by x
∴ b = ps + qr
∴ c = rs
∴ a = p * q
∴ b = p * s + q * r
∴ c = r * s
3 = q/11....multiply both sides by 11, this cancels out the 11's on the right
11 * 3 = q
33 = q
Answer:
B. y = x² - 3x - 10
Step-by-step explanation:
<em>good luck, i hope this helps :)</em>
Answer:
ok im not good at math but les see how this goes errr
Step-by-step explanation:welp i think it s35 beAZcausee im smART :))))
your welcome
you can thank me later :))\
Answer:
<u>After factorizing the equation on the numerator, we simplify and the answer is: x + 2</u>
Step-by-step explanation:
1. Let's simplify the following expression:
x squared plus 3 x plus 2 over x plus 1
(x ² + 3x + 2) / (x + 1)
Now, we are going to factorize the numerator, this way:
(x + 2) (x + 1) / ( (x + 1)
x * x = x ²; 2x + x = 3x ; 2 * 1 = 2 ⇒ x² + 3x + 2
We simplify (x + 1) both in the numerator and in the denominator and we have:
<u>x + 2</u>