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2 years ago

11

The Great Rope Company sells a rope that is 5 feet long. Juna wants to make sections that are 1/3 foot long. How many sections w

ill Juna be able to make?

1 answer:

vova2212 [387]2 years ago

8 0

5/1 ÷ 1/3=5/1 • 3/1= 15
Juna will be able to make 15 sections.

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Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

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2 years ago

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Lady bird [3.3K]

Tan(58)=10/x
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The area of cross section of the end A of a U tube is 0.01 m square. The area of cross section at the end B is 0.1 m square. If

lisov135 [29]

Area=0.1m^2(B),0.01m^2(A)
Force=100N,F1

$\\ \rm\longmapsto Pressure=\dfrac{Force}{Area}$

$\\ \rm\longmapsto\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}$

$\\ \rm\longmapsto F_1=A_1F_2/A_2$

$\\ \rm\longmapsto F_1=\dfrac{0.1(100)}{0.01}$

$\\ \rm\longmapsto F_1=\dfrac{10}{0.01}$

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2 years ago

Find the simple interest on the following hint I = prn

likoan [24]

Answer:

960

Step-by-step explanation:

I=PRN

I=4000(6%)(4)

You first want to convert your 6% to a decimal, you do so by dividing. 6/100= 0.06. Now you multiply to find your interest.

I=4000(0.06)(4)

I=4000(0.24)

I=960

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ololo11 [35]

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