Answer:
The Value of .
Step-by-step explanation:
We have Named the figure please find the attachment for your reference.
Given:
PR = y
QR = a
RS = b
PS = z
PQ = x
QS = 15
∠P = 90°
∠R = 90°
∠Q = 60°
∠S = 30°
We need to find the Value of 'a'.
Solution:
Now we know that:
In Δ PQS
∠P = 90°
∠S = 30°
Now we know that;
Substituting the given values we get;
Now we know that;
So we can say that;
Now In Triangle PQR.
∠R = 90°
∠Q = 60°
So we can say that;
Substituting the given values we get;
Now we know that;
So substituting the values we get;
By Using Cross Multiplication we get;
Hence The Value of .
F(-5) x g(-5)
f(-5) = -2(-5) - 7
f(-5) = 10 - 7
f(-5) = 3
g(-5) = -4(-5) + 3
g(-5) = 20 + 3
g(-5) = 23
f(-5) x g(-5) = 3 x 23 = 69
Your answer is 69
-2(x + 6) + 3 = -11x + 4(x + 4)
-2x - 12 + 3 = -11x + 4x + 16
-2x - 9 = -7x + 16
5x = 25
<em>x = 5</em>
Hope this helps! :)
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