These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Answer:
15.08 m
Step-by-step explanation:
The angle XZW :
XZW + 108° = 180°
XZW = 180° - 108°
XZW = 72°
Length of an arc = θ / 360 * πd
d = diameter = XV = 24
Length of arc XW = (72/360) * π * 24
Length of arc XW = 15.0796
Length of XW = 15.08 m
Answer:
Whereby circle 
P can be obtained from circle O by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, O is similar to P
Step-by-step explanation:
The given center of the circle O = (-2, 7)
The radius of O, r₁ = 5
The given center of the circle P = (12, -1)
The radius of P, r₂ = 12
The similarity transformation to prove that O and P are similar are;
a) Move circle O 14 units to the right and 8 units down to the point (12, -1)
b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4
Therefore, the radius of circle O is increased by 2.4
We then obtain O' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle P
∴ Circle P can be obtained from circle O by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, O is similar to P.
Answer: 15 and 1/4
Step-by-step explanation:
3 + 4 + 3 + 4 + 3/16+3/16+7/16 + 7/16
14 + 20/16
14+ 1 4/16
15 and 1/4
