Answer:
Step-by-step explanation:
The given cylindrical equation is
Multiply both sides by r.
.... (1)
The required formulas are
Substitute 
in equation (1).
Add 1 on both sides.
![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
It is the equation of a circle centered at (0,1) with radius 1.
Therefore, the equation in rectangular coordinates is .
Answer:
m= -1
I hope this helped, have a great day!! <3
Answer:
y = (3/2)x + 11/2
Step-by-step explanation:
As we move from the point (-3, 1) to the point (3, -3), x increases by 6 and y decreases by 4. Thus, the slope is
m = rise / run = 6/4 = 3/2.
Subbing the knowns into the general point-slope form of the equation of a straight line, we get
y - 1 = (3/2)(x - [-3]), or y - 1 = (3/2)(x + 3).
This is equivalent to y = (3/2)x + 9/2 + 1, or y = (3/2)x + 11/2.
I believe this is called scaling. This is the word that I am associating with your definition, as well as what many internet sources say. I am not 100% sure, but I think this is correct. Hope this helps.
Answer:
Bottom left graph
Step-by-step explanation:
We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:
−2x + y ≤ 4 >> Original Standard Equation
+ 2x + 2x
_________
y ≤ 2x + 4 >> Slope-Intercept Equation
−2[0] + 0 ≤ 4
0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]
[We shade the part of the graph that does not contain the origin, which is the left side.]
So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.
** By the way, you meant 
because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.
I am joyous to assist you anytime.
