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2 years ago

HELP :(

Mathematics

1 answer:

puteri [66]2 years ago

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Someone is answering the question.

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An atom that becomes positively charged due to the loss of one or more electrons is referred to as a/an proton. cation. . base,

steposvetlana [31]

Answer:

cation.

right on the test, Mark brainlieste

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

If p(x) = x^2 + 7x + 3 is divided by x + 4, the remainder is <br> a0

Sphinxa [80]

Hope this helps you!

4 0

2 years ago

9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly

zavuch27 [327]

Answer:

$9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69$

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

$A=P(1+\frac{r}{n})^{nt}$ ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27$

10) Aubrey Daniel's case:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07$

11) As for Angelo, similarly to Alicia.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87$

12) Simpson's. For semiannual n=2

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95$

13) Jana Lacey amount:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69$

6 0

2 years ago

Pls send help my waayyy

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

110 / 22 = 5 inches per picket

equation is y = 5x

3 0

3 years ago

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tail

WINSTONCH [101]

Answer: Two-tailed test.

Population mean is the parameter which is tested.

Step-by-step explanation:

Given : $H_0: \mu=105$

$H_1:\mu\neq105$

We know that , the alternative hypothesis ( $H_1$ ) indicates kind of the hypothesis test we need to perform whether left-tailed, right-tailed, or two-tailed.

Here, the alternative hypothesis ( $H_1$ ) is two-tailed, so the hypothesis test is a two-tailed test.

Also, the parameter present in the hypothesis is $\mu$ which is a symbol to represent the population mean.

Thus , Population mean is the parameter which is tested.

8 0

2 years ago