The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
By evaluating the linear equation, we can complete the table:
x: -2 | -1 | 0 | 1 | 2 |
y: -3 | -1 | 1 | 3 | 5 |
<h3>
How to complete the given table?</h3>
Here we want to complete the table:
x: -2 | -1 | 0 | 1 | 2 |
y: | | | | |
To get the correspondent values in the "y" row, you just need to evaluate the linear function in the given values of x.
Here the function is:
f(x) = 2x - 1
Evaluating it we get:
f(-2) = 2*(-2) + 1 = -3
f(-1) = 2*(-1) + 1 = -1
f(0) = 2*0 + 1 = 1
f(1) = 2*1 + 1 = 3
f(2) = 2*2 + 1 = 5
Now we just put these values in their correspondent place on the table.
x: -2 | -1 | 0 | 1 | 2 |
y: -3 | -1 | 1 | 3 | 5 |
If you want to learn more about linear functions:
brainly.com/question/1884491
#SPJ1
Answer:
X=3
Y=1
Step-by-step explanation:
In solving simultaneous equations, there are three methods, we have the elimination method, substitution method or graphical method. But for the purpose of this question, we would be using Elimination method.
5y-4x =-7 Equation 1
2y+4x=14 Equation 2
Since x has the same coefficient, it's easy to eliminate by adding up the two equations
5y+2y=7y
-4x+(+4x)=0
-7+(+14)=7
We have 7y=7
Divide both sides by 7,
y=7/7
y=1
Substituting for y in equation 2.
2(1)+4x=14
2+4x=14
4x=14-2
4x=12
x=12/4
x= 3
First, we are going to find the vertex of our quadratic. Remember that to find the vertex
of a quadratic equation of the form
, we use the vertex formula
, and then, we evaluate our equation at
to find
.
We now from our quadratic that
and
, so lets use our formula:
Now we can evaluate our quadratic at 8 to find
:
So the vertex of our function is (8,-72)
Next, we are going to use the vertex to rewrite our quadratic equation:
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.
We can conclude that:
The rewritten equation is
The x-coordinate of the minimum is 8
