So we are looking for the GCF which is the largest factor that the two numbers have in common, so you would want to circle all of the number that the two have in common. So it would be 2 twos and 2 X's (2,2,x,x). Which is the most numbers that the two have in common.
Well, since we know is a geometric sequence, we can always get the common ratio of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8 -32/8 = -4 <-- our common ratio
the first term is -2
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the
leading coefficient of denominator.
So then the limit would be 3/1 =
3.
Alternatively,
Hope this helps.
First you will use the slope formula:
M= Rise/Run = Y2-Y1/X2-X1
(0,13) (-4,10)
10-13
——— = -3/4 = 3/4
-4-0.
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical.
First, lets factor 8:
Now we can divide the power of the term, 3, by the index of the radical 2:
= 1 with a remainder of 1
Next, lets do the same for our second term
:
= 3 with a remainder of 1
Again, lets do the same for our third term
:
with no remainder, so this term will come out completely.
Finally, lets take our terms out of the radical:
We can conclude that the correct answer is the third one.