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1 year ago

Miguel and Kat are reading the same book. Miguel reads 5 times as many

Mathematics

1 answer:

n200080 [17]1 year ago

6 0

Answer:

$k=\dfrac{m}{5}$

Step-by-step explanation:

Let Kat reads k pages of the book.

Miguel reads 5 times as many pages of the book as Kat. So,

m = 5k ...(1)

Together they read 54 pages. i.e.

m+k = 54 ...(2)

From equation (1),

$k=\dfrac{m}5{}$

Hence, the equation that can be used to find how many pages Kat read is equal to $\dfrac{m}{5}$ .

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Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4

kramer

<u>Given</u>:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function $h(t)=-16t^2+55t+4$ represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

$30=-16t^2+55t+4$

$26=-16t^2+55t$

Adding both sides of the equation by 16t², we get;

$16t^2+26=55t$

Subtracting both sides of the equation by 55t, we have;

$16t^2-55t+26=0$

Let us solve the quadratic equation using the quadratic formula, we get;

$t=\frac{-(-55) \pm \sqrt{(-55)^2-4(16)(26)}}{2(16)}$

$t=\frac{55 \pm \sqrt{3025-1664}}{32}$

$t=\frac{55 \pm \sqrt{1361}}{32}$

$t=\frac{55 \pm 36.89}{32}$

$t=\frac{55 + 36.89}{32} \ or \ t=\frac{55- 36.89}{32}$

$t=\frac{91.89}{32} \ or \ t=\frac{18.11}{32}$

$t=2.9 \ or \ t=0.6$

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

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2 years ago

Use a transformation to solve the equation.

saul85 [17]

40/8 = 5

5 is the ans

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Answer:

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