Complete Question
Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.
Answer:
The probability is
Step-by-step explanation:
From the question we are told that
The probability that the test was accurate given that the person has cancer is
The probability that the test was accurate given that the person do not have cancer is
The probability that a person has cancer is
Generally the probability that a person do not have cancer is
=>
=>
Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as
=>
=>
The quadratic formula is =(-b+-sqrt(b^2-4ac))/2a
as you notice the term under the square root is b^2-4ac if it is postive then the equation clearly will have two real soultions if it is negative then the equation will have two imaginary soultion if it is zero then the the equation will have one soultion
so let us calculate b^2-4ac for our given equation
x^2=4x-5 so let us write it in general form which is ax^2+bx+c=0
subtracting 4x from both sides
x^2-4x=-5
adding 5 to both sides
x^2-4x+5=0
a=1,b=-4,c=5
b^2-4ac=(-4)^2-4(1)(5)=16-20=-4
which means the equation has two imaginary soultions
Answer:
3 x 10 = 30 man-days per house
Answer:
Okie when you do these you got to give all information
Step-by-step explanation: because people can help you instead of looking at a picture wonderin what they are they are supposed to do
Answer:
x = 0.5
Step-by-step explanation:
hope this helps!