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2 years ago

Help me work this out please

Mathematics

1 answer:

creativ13 [48]2 years ago

6 0

Answer:

∠DEF = 250°

Step-by-step explanation:

1. This shape is a hexagon (6 sides), so the interior angles should all add to 720°. Also worth noting: the problem says the obtuse angle DEF; this means it's the angle INSIDE the shape, not outside.

2. Add all the known angles, then subtract from the total degrees:

50 + 96 + 144 + 42 = 332

720 - 332 = 338

3. Because BC is parallel to ED, we can subtract 180 - 42 for the value of ∠EDC, which is 138°.

4. Add all the known values and subtract from 720 for the value of ∠DEF:

50 + 96 + 144 + 42 + 138 = 470

720 - 470 = 250°

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Answer:

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Step-by-step explanation:

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Please can I have an explanation also, I am terrible at these kinds of questions!

wlad13 [49]

Answer:

The fraction of the beads that are red is

Step-by-step explanation:

Algebraic Expressions

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

$\displaystyle \frac{r}{r+y+b} \qquad\qquad [1]$

Knowing that:

$\displaystyle \frac{r}{y}=\frac{2}{3} \qquad\qquad [2]$

$\displaystyle \frac{y}{b}=\frac{5}{4}$

Multiplying the equations above:

$\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}$

Simplifying:

$\displaystyle \frac{r}{b}=\frac{5}{6} \qquad\qquad [3]$

Dividing [1] by r:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}$

Substituting from [2] and [3]:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}$

Operating:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}$

The fraction of the beads that are red is $\mathbf{\frac{10}{37}}$

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Answer:

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Step-by-step explanation:

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