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2 years ago

Solve this polynomial: (22x^2+12x)/(2)

Mathematics

2 answers:

goldfiish [28.3K]2 years ago

5 0

Answer:she a she was a joke and she was

Step-by-step explanation:

ycow [4]2 years ago

3 0

Answer:

1 solution(s) found

See steps

Step by Step Solution

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STEP

Equation at the end of step 1

((0 - (22•3x2)) - 22x) - 8

STEP

Pulling out like terms

3.1 Pull out like factors :

-12x2 - 22x - 8 = -2 • (6x2 + 11x + 4)

Trying to factor by splitting the middle term

3.2 Factoring 6x2 + 11x + 4

The first term is, 6x2 its coefficient is 6 .

The middle term is, +11x its coefficient is 11 .

The last term, "the constant", is +4

Step-1 : Multiply the coefficient of the first term by the constant 6 • 4 = 24

Step-2 : Find two factors of 24 whose sum equals the coefficient of the middle term, which is 11 .

-24 + -1 = -25

-12 + -2 = -14

-8 + -3 = -11

-6 + -4 = -10

-4 + -6 = -10

-3 + -8 = -11

-2 + -12 = -14

-1 + -24 = -25

1 + 24 = 25

2 + 12 = 14

3 + 8 = 11 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 8

6x2 + 3x + 8x + 4

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (2x+1)

Add up the last 2 terms, pulling out common factors :

4 • (2x+1)

Step-5 : Add up the four terms of step 4 :

(3x+4) • (2x+1)

Which is the desired factorization

Final result :

-2 • (2x + 1) • (3x + 4)

Step-by-step explanation:

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2 years ago

Solve this polynomial: (22x^2+12x)/(2)​

Solve this polynomial: (22x^2+12x)/(2)