Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations!First let's clear the mess: 1. x= y-32. 6x-3y=6 Substitute 1 into 2: 6(y-3) -3y =66y - 18 - 3y = 6
3y = 24y = 8 Our units digit is 8 Substitute y= 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58
Answer:
5–3 = 2
8–5 = 3
12–8 = 4
17–12 = 5
x-17 should be 6, hence x = 6+17 = 23.
Step-by-step explanation:
Answer: 60
Step-by-step explanation:
V = w h l = 3 x 5 x 4 = 60
Hope this helped, if not i can do the problem again :)!
We are asked in the problem to devise a polynomial equation that has a GCF of 6 which means each of the terms can be divided to 6. For example: 6*(x^2 + x+1) = 6x^2 + 6x +6. This polynomial is created by multiplying each terms by the number 6 which is distinguished by factoring.
Answer:
X intercept is (-1,0)
Y intercept is (0,2)
Step-by-step explanation: