Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.
In which
So
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Note for probability, if it will never happen the P = 0. If it must happen P = 1.
So certain to happen:
C. P=1
Always start with what’s in the parentheses:)
Since 19 is a prime number it only goes into 1 and 19 so 1 times 19 is the only possible answer
First you would follow the Order Of Operations:
Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction
Second step: You will add 6 and 4 together since addition came before subtraction in the Order Of Operations.You would get 10.
Your equation should now look like: 13-10.
Last step: You would subtract 10 from 13 since there are no other numbers
Your answer should then be: 3
HOPE THIS HELPS! ^_^
