Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
Answer:
The answer to your question is 43
Step-by-step explanation:
2x³ + 8x² - 5x + 5 / x - 2
Process
1.- Use synthetic division
2 8 -5 5 2
4 24 38
2 12 19 43
Quotient 2x² + 12x + 19
Remainder 43
Answer:
x3squared-3x2squared-18x
Step-by-step explanation:
1 Expand by distributing terms.
({x}^{2}-6x)(x+3)(x
2
−6x)(x+3)
2 Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd.
{x}^{3}+3{x}^{2}-6{x}^{2}-18xx
3
+3x
2
−6x
2
−18x
3 Collect like terms.
{x}^{3}+(3{x}^{2}-6{x}^{2})-18xx
3
+(3x
2
−6x
2
)−18x
4 Simplify.
{x}^{3}-3{x}^{2}-18xx
3
−3x
2
−18x
Answer:
16
Step-by-step explanation:
(f - g)(5) = f(5) -g(5)
From the tables, ...
f(5) = 29
g(5) = 13
Your desired function is ...
f(5) -g(5) = 29 -13 = 16
Answer:
Perimeter=25 units
Area= 43 units^2
Step-by-step explanation:
one side = 5 units so perimeter is 5x5=25
split into 5 equal triangles
base =5, height =3.44, formula for area=(base)(height)(0.5)
area of each triangle =(5)(3.44)(0.5)=8.6
entire area=5(8.6)=43