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2 years ago

How many moles of I2 are in 8.23 moles of NaI ?

Chemistry

1 answer:

OleMash [197]2 years ago

3 0

Answer: 4.12

Explanation:

we know that the given mol is 8.23 mol and they are 2NaI and I2 so we will write the equation like this.

8.23mol NaI x 1mol of I2 ÷ 2molNaI = 4.115≅ 4.12 mol of I2

we placed NaI at the bottom to cancel out with the 8.23 mol of NaI

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Pentanitrogen heptachloride formula

Marianna [84]

Answer:

Explanation:

this is the answer hope it helps!(:

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2 years ago

What kind of orbital is occupied by the lone pair electrons in caffeine molecule?

Nataly [62]

The middle nitrogen has two sigma bonds and one pi bond. You know that one p orbital is used in the double bond and two sp2 orbitals are involved in the sigma bond. This leaves one sp2 orbital for the lone pair to occupy.

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2 years ago

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

2 years ago

When data does not support your hypothesis in an experiment, you must revise what

Blababa [14]

state what the lab is about, that is, what scientific concept (theory, principle, procedure, etc.) you are supposed to be learning about by doing the lab. You should do this briefly, in a sentence or two. If you are having trouble writing the opening sentence of the report, you can try something like: "This laboratory experiment focuses on X…"; "This lab is designed to help students learn about, observe, or investigate, X…." Or begin with a definition of the scientific concept: "X is a theory that…."

2. give the necessary background for the scientific concept by telling what you know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab). In relatively simple labs you can do this in a paragraph following the initial statement of the scientific concept of the lab. But in more complex labs, the background may require more paragraphs.

6 0

3 years ago

Select the correct answer. What is heat of vaporization? A. It is the heat required to change a substance’s temperature by 1°C.

Luba_88 [7]

D. It is the heat required to change a gram of substance from a liquid to a gas.

Explanation:

The heat of vaporization is the heat required to change a gram of substance from a liquid to a gas.

It is also known as the enthalpy of vaporization.
The heat of vaporization is the quantity of heat needed to change one gram of a substance from liquid to gas.
This heat of vaporization is dependent on the pressure conditions the process is taking place.
Different liquids have their heat of vaporization.

learn more:

Heat of vaporization brainly.com/question/9529654

#learnwithBrainly

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2 years ago