All categories

1 year ago

The diagram shows a triangle. 490 880 What is the value of v? V =

Mathematics

2 answers:

wolverine [178]1 year ago

5 0

Answer:

the answer is 43

Step-by-step explanation:

this is so simple

the first thing that u have to remember or there is a rule

the rule is : that all the three angels added up equal to 180 degrees

so that means 88+49+v=180

88+49+v=180 first combine like terms

137+v=180 now subtract both sides by 137

v= 43

ANSWER CHECK

88+49= 137

137+ 43= 180

Step2247 [10]1 year ago

3 0

Answer:

43°

Step-by-step explanation:

The first thing you should do is make the equation. We should know that the sum of all the angles is 180. So it should look like this...

$49+88+x=180$

Combine like terms:

$137+x=180$

Subtract the 137 on both sides:

$x= 43$

That's it the value of v is 43°.

You might be interested in

3 less than the quotient of 20 and x

UkoKoshka [18]

It would be (20/x) -3

3 0

2 years ago

3. There are 124 acorns laying on the ground in your yard, it is predicted that the number of acorns will

Gennadij [26K]

Answer:

507,409

Step-by-step explanation:

if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.

30 ÷ 5 = 6

so we only have to quadruple the acorns 6 times.

if we start off with 124 acorns, this is what it will look like:

Day 0: 124 acorns

Day 5: 124 x 4 = 496 acorns

Day 10: 496 x 4 = 1984 acorns

Day 15: 1984 x 4 = 7936 acorns

etc... until day 30.

Day 30: 507904 acorns

I hope this was helpful :-)

5 0

2 years ago

In a game between two teams a and b, john is set to win 200 dollars if a wins, and 100 dollars if b wins. john calculates his ex

My name is Ann [436]

According to his calculations, b has a 3/10 chance to win

7 0

2 years ago

#54 Simplify and write the answers using positive exponents only.

kramer

Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
$( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}$ =
$( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}$ =
$(2^{-3})((m^2)^{-3})((n^{-4})^{-3})$ =
$( \frac{1}{2^3})(m^{-6})(n^{12})$ =
$( \frac{1}{8} )( \frac{1}{m^6})(n^{12})$ =
$\frac{n^{12}}{8m^6}$

8 0

2 years ago

What number multiples to -1 and adds to -50

koban [17]

Z: is the number

[Z*(-1)]+(-50)
(-Z)+(-50)
-Z-50

<span>I hope it helps you :)</span>

5 0

2 years ago