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2 years ago

A circle has a radius of 8 centimeters. The measure of the arc of the

Mathematics

1 answer:

Gnesinka [82]2 years ago

3 0

Answer: 10.1

Step-by-step explanation:

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A quadratic equation that can be written as the difference of squares has...

quester [9]

Answer: C two solutions

Step-by-step explanation:

The Difference of Two Squares theorem says that any time an equation may be written as a difference between squares A² - B² = 0 it may be rewritten as two products, the sum and difference of the square roots (A + B) (A - B)

Hope this helped :)

6 0

2 years ago

Read 2 more answers

What’s the correct answer for this ?

pickupchik [31]

Answer:

Blank 1) 150

Blank 2) (3)²

3) (4)²

4) (x+3)²

5) (y-3)²

6) (x+3)²+(y-3)² = 100

6 0

2 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

2 years ago

Read 2 more answers

Help me please thank you

Anuta_ua [19.1K]

$S\frac{O}{H}C\frac{A}{H}T\frac{O}{A}$ or $Sin\frac{Opposite}{Hypotenuse} Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}$

The hypotenuse is the longest side of the triangle. The opposite is the side that is across from a point/angle. The adjacent is the side next to a point/angle.

At ∅ (pretend that's theta LOL), 17 is the hypotenuse, 8 is the opposite side, and 15 is the adjacent side.

So:

sin ∅ = Opposite/Hypotenuse

sin ∅ = $\frac{8}{17}$