Answer:
We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on. We say that f(x) has a relative (or local) minimum at x=c iff(x)≥f(c) f ( x ) ≥ f ( c ) for every x in some open interval around x=c .
Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
Answer:
C, D, and E are correct
Step-by-step explanation:
p(2)= 1/6; p(3)= 1/6; p(4)= 1/6; 1/6=1/6=1/6
p(1)= 3/6; 3/6=1/2
p(4) = 1/6; There are six sections and one section is labeled<em> '4' </em>
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Hope this helped! ;p