<span>-3m - [2m + (5 - m)] + 7
= -3m - 2m - 5 + m + 7
= -4m + 2
or
= 2 - 4m</span>
Answer:
We want to reduce type II error we carry out the test using a larger significance level (such as 0.10) and not a small significance level α (such as 0.01).
Step-by-step explanation:
Type I error
- Rejecting the null hypothesis when it is in fact true is called a Type I error.
- It is denoted by alpha, α that is the significance level.
- Lower values of alpha make it harder to reject the null hypothesis, so choosing lower values for alpha can reduce the probability of a Type I error.
It is given that the consequences of a Type I error are not very serious, but there are serious consequences associated with making a Type II error.
Type II error
- This is the error when we fail to reject a false null hypothesis or accept a null hypothesis when it is true.
- Higher values of alpha makes it easier to reject the null hypothesis.
- So choosing higher values for alpha can reduce the probability of a type II error.
- The consequence here is that if the null hypothesis is true, increasing the value of alpha makes it more likely that we make a Type I error.
Since, we want to reduce type II error we carry out the test using a larger significance level (such as 0.10) and not a small significance level α (such as 0.01).
This will increase type I error but that is okay since we do not have serious consequences for it.
The expression is an illustration of the summation notation
The expanded form of the summation notation 
is 0^4 + 1^4 + 2^4 + 3^4+4^4
<h3>How to determine the expanded form</h3>
The summation notation is given as:
The above summation notation represents the sum of the numbers raise to the power of 4, from 0 to 4
So, we have:
Hence, the expanded form of is 0^4 + 1^4 + 2^4 + 3^4+4^4
Read more about summation notation at:
brainly.com/question/16599038
Answer:
n = 4/3
Step-by-step explanation:
-7(-9+5n) = 31-9n
63-35n = 31-9n
32-35n = -9n
32 = 24n
32/24 = 24n/24
4/3 = n
The area of a square is calculated using the formula s², where s is a side length of the square.
If we plug in our known quantities, we get the equation:
121 = s²
In order to get rid of the square, we must perform the inverse operation, which is to square root.
√121 = s
11 = s
Therefore, a side length of the square would be A. 11 in.
