Answer:
The volume of the gas sample at standard pressure is <u>819.5ml</u>
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.
1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,
Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.
=735-42.2=692.8 mmhg
Now
By using combined gas law equation:
Here are standard pressure and temperature respectively.
we have
Substituting value, we get
Answer:
A and C
Explanation:
The term formula unit is use to indicate Simple-Whole Ratios of ions in a compound. KEY WORD! RATIO!
Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13
From ideal gas equation P V = m RT
⇒ P =
Put all the values in above formula we get
⇒ P = × 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Explanation:
According to the Handerson equation,
pH =
or, pH =
Putting the given values into the above equation as follows.
pH =
5.0 = 6.0 + log \frac{\text{conjugate base}}{\text{acid}}[/tex]
= -1.0
or,
= 0.1
Therefore, we can conclude that molar ratios of conjugate base to weak acid for given solution is 0.1.
Answer:
true
Explanation:
we have many sattelites that are seen by many astounouts in space by telescope but more than half space is not discoverd