Answer:
3 can go into 77 25 times.
Given
- f(n) values for n=1,2,3,4
- possible candidates for the function
Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.
N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]
N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]
Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]
Solution: f(n)=4(3^(n-1))
Answer:
55+8.5x=123
Step-by-step explanation:
The 55 represents the flat fee, the 8.5 represents the daily charge, x represents the number of days she rented it for, and 123 is the total amount
V = a²h/3
Plugging values in we get 8.67X10^7, or 86,700,000
Perimeter formula
p = 2l + 2w
I reverse left-right side
2l + 2w = p
Move 2l to the right
2l + 2w = p
2w = p - 2l
Move 2 to the right
2w = p - 2l
w = (p - 2l)/2
Summary
p = 2l + 2w
2l + 2w = p
2w = p - 2l
w = (p-2l)/2
