We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .
The equation and the point is;
We know that for two lines to be perpendicular, the product of their slopes should be -1.
Therefore, the slope of the perpendicular should be;
The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;
Inserting all values, we have,
That is the final answer.
y = mx + b
To find the slope(m), you use the slope formula:
You plug in the points into the equation.
The slope is 0
y = 0x + b
Any number multiplied by 0 is 0. So:
y = b
To find b, you plug in the y value of either of the points.
-4 = b
Your equation is:
y = -4 (This is a horizontal line)
Multiply the fraction by both things in the parenthesis.
Answer:
divided by 5
Step-by-step explanation:
Hope that helps!
Answer:
m(WXY) = 224°
Step-by-step explanation:
Measure of inscribed angle = ½ the measure of intercepted arc
Therefore:
m<C = ½*m(WXY)
112° = ½*m(WXY) (substitution)
Multiply both sides by 2
2*112° = m(WXY)
224° = m(WXY)
m(WXY) = 224°
