Formula: NA2S2O3. Valency: 2
We can use the heat equation,
Q = mcΔT
where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Q = 11.2 kJ = 11200 J
m = <span>145 g
</span>c = ?
ΔT = (67 - 22) °C = 45 °C
By applying the formula,
11200 J = 145 g x c x 45 °C
c = 1.72 J g⁻¹ °C⁻¹
Hence, specific heat of benzene is 1.72 J g⁻¹ °C⁻¹.
Answer:
6
Explanation:
the value is 6 because its an even number
Answer:
2Zn + 2HCI ➡️ ZnCI2 + H2
LHS of equation
Z = 2
H = 2
Cl = 2
RHS of equation
Zn = 1
Cl =2
H =2
as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass
Explanation:
the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.
