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2 years ago

Please help me asap

Mathematics

1 answer:

77julia77 [94]2 years ago

5 0

Answer:

1929r9fij1j2jed8f82u2hfisj

Step-by-step explanation:

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Please help, will give 5 stars

Alexus [3.1K]

Function 1
rate of change = (80-100)/(2-1) = -20
y = -20x + 120

function 2
y = -18x + 120
rate of change = -18

answer
function 2 shows a greater rate of change

7 0

2 years ago

Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

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2 years ago

4 quarters are equal in value to 10 dimes.

bija089 [108]

Answer:

Step-by-step explanation:

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3 years ago

Solve 7 plus x equals 13

Paul [167]

7 + 6 = 13, so x = 6

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2 years ago

Read 2 more answers

What position did Theodore Roosevelt hold before he became president?

BlackZzzverrR [31]

Answer:

He served as Assistant Secretary of the Navy under President William McKinley

hope i helped

-lvr

3 0

2 years ago

Please help me asap​

Please help me asap