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2 years ago

Find the slope of the line that goes through (6, 10) and (2,5)

Mathematics

2 answers:

Paul [167]2 years ago

8 0

Answer:

-5/-4

Step-by-step explanation:

m=y2-y1/x2-x1

m=5-10/2-6

m=-5/-4

-Dominant- [34]2 years ago

6 0

Answer:

1.25

Step-by-step explanation:

Slope m= 5-10/ 2-6

m= -5/-4

m= 1.25

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6th grade math, help pleasee:)

Debora [2.8K]

Answer:

1/5 cup

Step-by-step explanation:

Sugar: water

1 5

We want 1 cup water, so divide each side by 5

1/5 : 5/5

1/5 : 1

There is 1/5 cup sugar to 1 cup water

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2 years ago

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A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

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2 years ago

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1 16

kifflom [539]

Answer:

Step-by-step explanation:

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2 years ago

How do you round 3,284,994 to the nearest ten thousand

Ghella [55]

3,290,000 is the answer

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2 years ago

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PLEASE ANSWER THIS 30 POINTS BRAINLIEST WILL BE GIVEN PICTURE INCLUDED!!

den301095 [7]

The first step is to quickly factor each of the five equations... to do so, find the right factors of the 3rd given number so that they add up in an equal number to the second number... 14 = -7 • -2 and -9 = -7 + -2

a^2 - 9a + 14 = 0
(a - 7) (a - 2)

a - 7 = 0, a = 7
a - 2 = 0, a = 2

{2,7}

a^2 + 9a + 14 = 0
(a + 7) (a + 2)

a + 7 = 0, a = -7
a + 2 = 0, a = -2

{-2, -7}

a^2 + 3a - 10 = 0
(a + 5) (a - 2)

a + 5 = 0, a = -5
a - 2 = 0, a = 2

{-5, 2}

a^2 - 5a - 14 = 0
(a - 7) (a + 2)
a - 7 = 0, a = 7
a + 2 = 0, a = -2

{-2, 7}

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2 years ago

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