1. Find the error & explain why it is wrong:

Mathematics

2 answers:

allsm [11]2 years ago

6 0

When we open the bracket on left side square of 3 is 9
But on right side it is written 6

quester [9]2 years ago

4 0

That’s the problem. Where are the steps?

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hamburgers cost $2 per lbs and chicken costs $3 lbs and you only have $30 to spend and expect At least 3lbs of hamburger

kicyunya [14]

If you want at least 3 pounds of hamburgers, then $6 is enough to buy those 3 pounds of hamburgers. If you ONLY buy 3 Pounds, then you also have enough for 4 pounds of chicken. $3 a pound x 4 = $12. You have 2 dollars left to spare, which means you can buy another pound of hamburgers. So 4 pounds each are able to be purchased.

4 0

2 years ago

A triangle T is bounded (on three sides) by the lines x = 6, y = 0, and y = 3 2 x. A rectangle of width w is inscribed inside T.

Viktor [21]

Answer:

33.85 units^2

Step-by-step explanation:

you must first draw the triangle on the plane using the equations (see

attached file), you will have a right angle triangle with a height of 192 and a base of 6.

then you calculate the angle with the tangent function = 88.21

Then you use the small triangle to find the value of a (see attached file).

Finally, you propose an equation for X to find one of the sides of the triangle, once you have x squared it, and you already have the area,

i attached procedure

7 0

2 years ago

What are the signs of the x- and y-coordinates of points within each of the four quadrants in the coordinate plane?

Naily [24]

In the first quadrant the signs would be (x,y) in the second quadrant they would be (-x,y) in the third (-x,-y) and the fourth (x,-y)

5 0

2 years ago

Due 4/29/22. add explanation to please if you can, so that i can understand better

vagabundo [1.1K]

Answer:

240 ÷ 5 = 48

Please Mark Brainliest If This Helped!

8 0

2 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$