<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>
<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>
To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,
Solve the inequality
Subtract 1000 from both sides
Time cannot be negative
Therefore,
t < 6.61
And the inequality used is:
Answer
x = 3981071.7055
y = 3981.0717
x > y
Step by step explanation
First let's find the value of x and y by taking anti - log.
log X = 6.6
X = log^ -1 (6.6)
X = 3981071.7055
Similarly,
log Y = 3.6
Y = log ^(-1) 3.6
Y = 3981.0717
Once we found the values of X and Y , we can easily compare them.
Here x > y
Hope you will understand the concept.
Thank you. :)
Answer: 502.65
Step-by-step explanation: A= 2πrh + 2πr^ this is the formula for solving the surface area so now you must substitute
2·π·5·11+2·π·5^
6.28 · 55 + 2 π · 25
add and you will get 502.65 hope this helps mark me brainliest if it did