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2 years ago

PLEASE HELP RIGHT NOWWWW

Mathematics

1 answer:

Roman55 [17]2 years ago

8 0

Answer:

uhm i hope i get this right i think it is .76

Step-by-step explanation:

hopefully i get that right

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Which point would map onto itself after a reflection across the line y = –x?

Softa [21]

Answer:

its D

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

If 7x=3y and 5y=7z then X/Z?

Aleks04 [339]

Answer:

3/5=x/z

Step-by-step explanation:

7x=3y

7(3)=3(7)

21=21

5y=7z

5(7)=7z (plug in the seven from the first step)

35=7z

then divide both sides by 7

5=z

therefore, X/Z=3/5

7 0

3 years ago

The volume of a barrel of oil is 257166 cm3 round this figure to the nearest hundred thousand

Fudgin [204]

Answer: Hope this helps :D

the answer is 300000 cm3

Step-by-step explanation:

3 0

1 year ago

Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a

LekaFEV [45]

To make this a little clearer, let's give the pairs of inequalities the same denominator:

Question 1:
 $\frac{11}{15}$ ? $\frac{5}{7}$
First, apply the common denominator to the first fraction:
$(\frac{11}{15})7 \\ \frac{11}{15} * \frac{7}{7} \\ \frac{11*7}{15*7} \\ \frac{77}{105}$
Do the same for the second: $15( \frac{5}{7}) \\ \frac{5}{7}* \frac{15}{15} \\ \frac{5*15}{7*15} \\ \frac{75}{105}$
Nest, compare the two fractions:
$\frac{77}{105} \ \textgreater \ \frac{75}{105}$
Therefore:
$\frac{11}{15}$ > $\frac{5}{7}$

Question Two:
$\frac{5}{9}$ ? $\frac{7}{13}$
Apply the common denominator to fraction one:
$13( \frac{5}{9}) \\ \frac{5}{9} * \frac{13}{13} \\ \frac{5*13}{9*13} \\ \frac{65}{117}$
Fraction two:
$9(\frac{7}{13}) \\ \frac{7}{13} * \frac{9}{9} \\ \frac{7*9}{13*9} \\ \frac{63}{117}$
Evaluate:
$\frac{65}{117}$ > $\frac{63}{117}$
Therefore:
 $\frac{5}{9}$ > $\frac{7}{13}$

Hope this helps!

5 0

2 years ago

Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8.

murzikaleks [220]

Answer:

The answer is 10m + 7n - 14

Step-by-step explanation:

Q = 7m + 3n

R = 11 - 2m

S = n + 5

T = -m - 3n + 8

[Q - R] + [S - T] is

[ 7m + 3n - (11 - 2m) ] + [ n + 5 - ( - m - 3n+8)]

Solve the terms in the bracket first

That's

( 7m + 3n - 11 + 2m ) + ( n + 5 + m + 3n - 8)

( 9m + 3n - 11 ) + ( m + 4n - 3)

Remove the brackets

That's

9m + 3n - 11 + m + 4n - 3

Group like terms

9m + m + 3n + 4n - 11 - 3

The final answer is

Hope this helps you

4 0

2 years ago