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2 years ago

12

-13 > x -43 solve the inequality and enter your solution as inequality comparing the variable to the solution

1 answer:

ipn [44]2 years ago

3 0

Answer:

30 > x

Step-by-step explanation:

-13 > x-43

-13 + 43 > x -43 + 43

30 > x

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The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

2 years ago

Problem PageQuestion It takes an older pump twice as long to drain a certain pool as it does a newer pump. Working together, it

umka2103 [35]

Answer:

It will take 6 hours for the new pump to drain the pool.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

Let the rate of new pump is given as x=W/t_1

Let the rate of the old pump is given as y=W/t_2

it is given that the time t_2=2t_1

So by substituting the values of t_2 in the rate equation of y

y=W/2t_1

y=(W/t_1*2)=x/2

Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes

x+y=W/4

x+x/2=W/4

3x/2=W/4

As x=W/t_1

3W/2t_1=W/4

Now as W is same on both sides so

3/2t_1=1/4

12=2t_1

t_1=6 hours

So it will take 6 hours for the new pump to drain the pool.

7 0

2 years ago

Find equation to this line

kondor19780726 [428]

Answer:

the equation of this line is y= 1x+6

8 0

2 years ago

plot the reflection of point A across the x-axis. what are the coordinates of the reflection of point A across the x-axis? what

dsp73

You reflect point A over the x-axis, double the distance from point a to the x-axis, then give the coordinates.

ex/ point A to the x-axis: 6, reflection: 12. coordinates (-6, 5)

8 0

2 years ago

Absolute value of +4 and -2

Greeley [361]

Answer:

4 and 2

Step-by-step explanation:

3 0

2 years ago

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