Ask question

Ask question

All categories

2 years ago

5

2.50 L of gas originally at 50 K is warmed to 80 K. If the pressure remains constant, which gas law needs to be used to find the

new volume?
Select one:
a.Charles law
b.Gay-Lussac’s law
c.Boyle’s law
d.Combined gas law

2 answers:

Sedaia [141]2 years ago

7 0

It is Charles law (a)

baherus [9]2 years ago

4 0

A. Charles law because The volume and temp of a gas at constant pressure are directly proportional to each other:

You might be interested in

Write the following number using Scientific notation : 13,215,296.50 *

ludmilkaskok [199]

Answer:

13.22x10^7

Explanation:

7 0

2 years ago

Classify each of the following properties by writing physical or chemical matter

Ivenika [448]

1. Physical matter
2. Chemical matter
3. Physical matter
4. Physical matter
5. Chemical matter
6. Physical matter.

6 0

2 years ago

Although both fission and fusion generate energy, fusion produces much more energy than nuclear fission and produces less nuclea

noname [10]

I believe that is true.

3 0

2 years ago

Read 2 more answers

Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th

WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]$

We are given:

$\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ$

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0

2 years ago

In order to predict whether or not a single replacement reaction takes place you need to consult a chart that shows the

erastova [34]

<span>Activity series of metals. it is a series of metals based on their reactivity from highest to lowest. Potassium occupies the top most level of reactivity. The reactivity means the ability to displace hydrogen gas from water and acid solutions.</span>

6 0

2 years ago