I hope this helps you
6+4.10-5
6+40-5
46-5
41
They all can be split up to 6 groups because 12+18=30 so each group will have 5 kids in it.
Assuming you mean f(t) = g(t) × h(t), notice that
f(t) = g(t) × h(t) = cos(t) sin(t) = 1/2 sin(2t)
Then the difference quotient of f is
Recall the angle sum identity for sine:
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
Then we can write the difference quotient as
or
(As a bonus, notice that as h approaches 0, we have (cos(2h) - 1)/(2h) → 0 and sin(2h)/(2h) → 1, so we recover the derivative of f(t) as cos(2t).)
The acceleration is defined as the ratio between the change in velocity and the time elapsed to perform such a change.
These "changes" are indicated with the capital greek letter delta, , and when you write you mean the difference between the finial and the inital values of the variable x:
So, the acceleration is defined as
In this case, the initial velocity is 35, the final velocity is 65. Assuming we start the clock at the beginning of the observation, the inital time is 0 and the final time is 5. So, we have
m/s^2
Answer:
Area of the sector = 29.48 square miles.
Step-by-step explanation:
Given:
Radius of a circle = 13 miles
Angle bounded by the arc = 20 deg
To find
Area of the sector bounded by 20 degrees.
Note: Area of a sector =
Plugging the values in the equation.
⇒
⇒
⇒ square-miles
So the area of the sector bounded by 20 degree arc is 29.48 square miles.