Help me please!!!! The question is in the picture^^^
1 answer:
You might be interested in
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
<em>True </em>
Step-by-step explanation:
<em>Rate Of Change Of Functions </em>
Given a function y=f(x), the rate of change of f can be computed as the slope of the tangent line in a specific point (by using derivatives), or an approximation by computing the slope of a secant line between two points (a,b) (c,d) that belong to the function. The slope can be calculated with the formula
If this value is calculated with any pair of points and it always results in the same, then the function is linear. If they are different, the function is non-linear.
Let's take the first two points from the table (1,1)(2,4)
Now, we use the second and the third point (2,4) (3,9)
This difference in values of the slope is enough to state the function is non-linear
Answer: True