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2 years ago

Simplify the following equation:

Mathematics

1 answer:

stich3 [128]2 years ago

5 0

Answer:

Step-by-step explanation:

The Answer Is Just D. Don't Ask Me How Just Trust Me It's D. Sorry I Can't Give An Explanation! I Not That Smarts. But It Is D! Have A Good Day!

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The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?

BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
$A_{n}=A_{1}+(n-1)d$

$A_{n}$ is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so $A_{1}=47$
d=-2 because the question gives you that

$A_{n}=A_{1}+(n-1)d$
 $A_{29}=47+(29-1)(-2)$
 $A_{29}=47+(28)(-2)$
 $A_{29}=47+-56$
 $A_{29}=-9$

The answer is A. -9.

 

The answer is C. 158

For the second one, it gives you $A_{1}=4$ and $A_{}=18$
You can use this to find d

 $A_{n}=A_{1}+(n-1)d$
 $A_{3}=4+(3-1)d$
 $18=4+(3-1)d$
 $18=4+2d$
 $14=2d$
 $7=d$

Now you can just solve using the equation normally.
 $A_{n}=A_{1}+(n-1)d$
 $A_{23}=4+(23-1)(7)$
 $A_{23}=4+(22)(7)$
 $A_{23}=4+154$
 $A_{23}=158$

The answer is C. 158

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The square root of Pi is approximately 1.77245.

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Jamie cell phone service costs $21 per month plus $0.25 for each level call in Long Distance calls are extra last month Jamie's

vitfil [10]

36.64-21=15.64
15.64-6.14=9.5
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Sir John Franklin was an explorer who traveled in Canada and the United States he was 33 years old when he began exploring North

Dmitry_Shevchenko [17]

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Describe the next figure in each pattern. Then draw the figure

madreJ [45]

The first figure has 3 angles, the second one has 4 angles, the third one has 5 angles so the next one will have 6 angles.

The violet figures inside stick with each side of the outer figures in the middle, so the last figure will look more less like in the attachment.

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