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2 years ago

In an electronics store, an iPod is $75. The sales tax is 7.5%. What is the cost of the iPod?

Mathematics

1 answer:

castortr0y [4]2 years ago

3 0

Answer:

$80.625

Step-by-step explanation:

$75 for the iPod times 0.075 = 5.625 which is the sales tax.

Then $75 (Cost of iPod) + 5.625 (Sales Tax) = $80.625 (Price of the iPod including the sales tax)

Sorry, if I am wrong. I tried my best and Hope this helps ;)

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1 year ago

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Which algebraic expression represents the phrase below? five times the sum of a number and eleven, divided by three times the su

anyanavicka [17]

The overall algebraic expression will be: $\frac{5(x+11)}{3(x+8)}$

Definition of algebraic expression -

An expression obtained by a finite number of the fundamental operations of algebra upon symbols representing numbers.

Five times the sum of a number and eleven, divided by three times the sum of the number and eight.

Let the number be x.

Five times the sum of a number and eleven means 5 multiplied to the sum of x and 11. In expression this will be written as:

5(x + 11)

Three times the sum of the number and eight means 3 multiplied to the sum of x and 8. In expression this will be written as:

3(x + 8)

So, the overall algebraic expression will be: $\frac{5(x+11)}{3(x+8)}$

Learn more about algebraic expression

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10 months ago

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

$H_0 : \sigma = 10$

$H_1 : \sigma \neq 10$

The test statistics can be computed as follows:

$X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}$

$X^2 = \dfrac{(36 -1)10.1^2 }{10^2}$

$X^2 = \dfrac{(35)102.01 }{100}$

$X^2 = \dfrac{3570.35 }{100}$

$X^2 =35.704$

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703 ( to four decimal places)

Decision Rule : To reject the null hypothesis if P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.