Answer:
Please check the explanation.
Step-by-step explanation:
- As we know that the values in the table represent a function only if there there is only 1 input for every output.
Given the table 1
x y
-12 2
-10 10
0 -2
5 -6
8 -11
15 -15
From the table, it is clear that for each input there exists a unique output.
i.e.
According to the given table,
y = 2 at x=-12
y = 10 at x=-1
0
y = -1 at x=0
y = -11 at x=8
y = -15 at x=15
From the table, it is clear that for each input x, it has a unique output y.
Hence, table 1 is a function.
Given the table 2
x y
9 -18
-20 0
-6 1
-17 16
9 17
11 19
This table does not produce a function, because the input x=9 produces two outputs.
i.e.
at x = 9, the y = -18
at x = 9, the y = 17
Therefore, the table 2 does not represent a function.
Answer:
The number of boys are 18 and the number of girls are 30.
Step-by-step explanation:
The ratio of number of girls to the boys = 3 : 5
Let the number of girls is g and boys is b initially.
b : g = 3 : 5
5 b = 3 g ..... (1)
Now, girls are 6 + g and boys are b - 9
So, the ratio is
(b - 9) : (6 + g) = 1 : 4
4 b - 36 = 6 + g
4 b - g = 42 .... (2)
From ( 1 ) and ( 2 )
And , g = 5 x 18/3 = 30
So, the number of boys are 18 and the number of girls are 30.
<h3>Isolate y on both equations then equate </h3>
- x²-3x+2y=-4
- 2y=-x²+3x-4
- y=-x²/2+3/2x-2
Now you can equate it with second one to get x
Answer: cos(x)
Step-by-step explanation:
We have
sin ( x + y ) = sin(x)*cos(y) + cos(x)*sin(y) (1) and
cos ( x + y ) = cos(x)*cos(y) - sin(x)*sin(y) (2)
From eq. (1)
if x = y
sin ( x + x ) = sin(x)*cos(x) + cos(x)*sin(x) ⇒ sin(2x) = 2sin(x)cos(x)
From eq. 2
If x = y
cos ( x + x ) = cos(x)*cos(x) - sin(x)*sin(x) ⇒ cos²(x) - sin²(x)
cos (2x) = cos²(x) - sin²(x)
Hence:The expression:
cos(2x) cos(x) + sin(2x) sin(x) (3)
Subtition of sin(2x) and cos(2x) in eq. 3
[cos²(x)-sin²(x)]*cos(x) + [(2sen(x)cos(x)]*sin(x)
and operating
cos³(x) - sin²(x)cos(x) + 2sin²(x)cos(x) = cos³(x) + sin²(x)cos(x)
cos (x) [ cos²(x) + sin²(x) ] = cos(x)
since cos²(x) + sin²(x) = 1
