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2 years ago

Round 5,278 to the nearest thousand.

Mathematics

2 answers:

alexgriva [62]2 years ago

7 0

Answer 5,000 if the number beside it is 4 or lower you round down, if it’s 5 or above you round up

Nata [24]2 years ago

7 0

5,000, a trick i learned in 2nd grade was, below four go to the floor( round down) above five climb the vine (round up)

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Which of the following statement(s) describes the rate of change of f over the interval 1.5 ≤ x ≤ 3? Select all that apply.

Vesnalui [34]

2 Answers: Choice B and Choice C

The rate of change is 2.

The rate of change is constant.

======================================================

Explanation:

The first point on the left is when x = 1.5 and it has a height of y = 1

The point (1.5, 1) is on the line.

So is the point (3,4) for similar reasoning.

Compute the slope between those points

m = (y2-y1)/(x2-x1)

m = (4-1)/(3-1.5)

m = 3/(1.5)

m = 2

The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3 is a part of.

Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.

6 0

1 year ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

2 years ago

The length of a rectangle is 5 inches shorter than double its width. The perimeter of the rectangle is 192 inches. Write a two-s

alukav5142 [94]

Answer:

Step-by-step explanation:

Givens

Let the width = x

Let the length = x + 5

Equation

2w + 2W = P

Solution

2x + 2(x + 5) = 192 Remove the brackets <=== Answer

2x + 2x + 10 = 192 Combine like terms

4x + 10 = 192 Subtract 10 from both sides

4x = 192 - 10

4x = 182 Divide by 4

4x/4 = 182/4

x = 45.5

8 0

2 years ago

When a sunfloweris 2 weeks old it is 38 centimeters tall when it is 6 weeks old it is 114 cm tall how tall is it when it is 3 ½

Anna11 [10]

2 wk --- 38 cm
3.5 wk --- x cm
x = 3.5 wk x 38 cm
---------------------
2 wk
x= 66.5 cm

5 0

2 years ago

Factor 20 please explain factors and answer I'm really bad at math

Leona [35]

5 0

2 years ago

Read 2 more answers