x+y=10
x-y=8, x=y+8
y+8+y=10
2y=2
y=1
So, x=10-y=10-1=9.
Numbers Would be 9 and 1.
A = 11 and b = 8 I’m pretty sure brosky
In the division rule you subtract the exponents<span> when </span>dividing<span> numbers with the same base. </span>One<span> rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = </span>0<span>,because </span>0/0<span> is indeterminate (it is like dividing </span>zero<span> by </span>zero<span>). No matter what number we use when it is raised to the </span>zero power<span> it will always be </span>1.
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to
, we can work backwards to add 11 to both sides. We see that
must be under the radicand, so the answer is
A.
Given:
To find:
The obtuse angle between the given pair of straight lines.
Solution:
The slope intercept form of a line is
...(i)
where, m is slope and b is y-intercept.
The given equations are
On comparing these equations with (i), we get
Angle between two lines whose slopes are is
Putting and , we get
Now,
and
and
and
, so it is an obtuse angle and , so it is an acute angle.
Therefore, the obtuse angle between the given pair of straight lines is 120°.