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Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
Answer:
4 large , 14 small
Step-by-step explanation:
35*x +20*(18-x)=420
35x +360-20x=420
35x-20x=420-360=60
15x= 60
x =4
4 large 14 small
3x - 10 < 2
3x < 2 + 10
3x < 12 Divide through by 3.
x < 12/3
x < 4
