B.) 10x-5 is equivalent to 6x – 5 + x + 3x
<h2>GOOD LUCK CHUCK :)))))))))</h2>
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
The slope of KH is 1
The slope of GJ is -1
The product of the slopes of the diagonals is -1
Therefore, KH is perpendicular to GJ
Answer:30000 just 5000+ six time
